((X+1)^1/2)-3x=1

Solution for ((X+1)^1/2)-3x=1 equation:

((X+1)^1/2)-3X=1

We move all terms to the left:

((X+1)^1/2)-3X-(1)=0

We add all the numbers together, and all the variables

-3X+((X+1)^1/2)-1=0

We multiply all the terms by the denominator


-3X*2)+((X+1)^1-1*2)=0

We add all the numbers together, and all the variables

-3X*2)+((X+1)^1=0

Wy multiply elements

-6X^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{-12}=0$